LeetCode Rotate Array

Description

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.

The original problem is here:

My Solution

I solve this problem in Python, as below:

class Solution:
    # @param nums, a list of integer
    # @param k, num of steps
    # @return nothing, please modify the nums list in-place.
    def rotate(self, nums, k):
        total_num = len(nums)
        temp_nums = nums[:]
        if(total_num <= k):
            k =  k % total_num
        begin_count = total_num - k
        for i in range(0,k):
            nums[i] = temp_nums[begin_count+i]
        for i in range(k,total_num):
            nums[i] = temp_nums[i-k]

        #return nums

    #The codes Under below is used for running
    #Don't submit them
    #nums = [1,2,3,4,5]
    #k = 3
    #S = Solution()
    #S.rotate(nums,k)
    #print nums

Note

One point should be noted is when k is larger than the length of the array, we should compute the modulus of k to the array length.


LeetCode Rotate Array
http://zhaoshuaijiang.com/2015/03/20/leetcode_rotate_array/
作者
shuaijiang
发布于
2015年3月20日
许可协议