# Description

Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not “two and a half” or “half way to version three”, it is the fifth second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

The original problem is here.
The original code is here.

# My Solution

I solve this problem in C++, as below:

``````/*
*Compare Version Numbers
*Author: shuaijiang
*Email: zhaoshuaijiang8@gmail.com
*/
#include<iostream>
#include<sstream>
#include<vector>
#include<string.h>
#include<math.h>
using namespace std;

class Solution {
public:
int compareVersion(string version1, string version2) {
vector<string> vec1 = str2Vector(version1);
vector<string> vec2 = str2Vector(version2);
int strLarger;
if(vec1.size() > vec2.size())
{
}
else if(vec1.size() < vec2.size())
{
}
vector<string>::iterator iter1,iter2;
for(iter1=vec1.begin(),iter2=vec2.begin();iter1<vec1.end()&&iter2<vec2.end();++iter1,++iter2)
{
strLarger = strCompare(*iter1,*iter2);
if(strLarger == 1)
return 1;
else if(strLarger == -1)
return -1;
else if(iter1==vec1.end()-1 && iter2==vec2.end()-1)
{
if(strLarger == 0)
return 0;
}
}
}
int strCompare(string str1, string str2)
{
int num1=str2Integer(str1);
int num2=str2Integer(str2);
if(num1>num2)
return 1;
else if(num1<num2)
return -1;
else
return 0;
}
int str2Integer(string str)
{
stringstream ss;
int num;
ss.clear();
ss.str("");
ss<<str;
ss>>num;
return num;
}
vector<string> str2Vector(string str)
{
string strNum, strTemp;
stringstream ss;
vector<string> strVec;
for(int count=0;count<str.size();++count)
{
if(count == str.size()-1)
{
ss.clear();
ss<<str[count];
ss>>strTemp;
strNum.append(strTemp);
strVec.push_back(strNum);
}
if(str[count] == '.')
{
strVec.push_back(strNum);
strNum.clear();
}
else
{
ss.clear();
ss<<str[count];
ss>>strTemp;
strNum.append(strTemp);
}
}
return strVec;
}
{
vec.push_back("0");
}
};
//The code below is used for test
int main()
{
string str1 = "1.0";
string str2 = "0.1";
Solution s;
int res = s.compareVersion(str1,str2);
cout<<"res="<<res<<endl;
//system("pause");
}
``````

# Note

Many situations should be considered, such as there are more than one “.”, the two versions have differet number of subversion and so on.