Description
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
Find the minimum element.
You may assume no duplicate exists in the array.
The original problem is here.
The original code is here.
My Solution
I solve this problem in C++, as below:
/*Find Minimum in Rotated Sorted Array
*Author: shuaijiang
*Email: zhaoshuaijiang8@gmail.com
*/
#include<iostream>
#include<stdlib.h>
using namespace std;
class Solution {
public:
int findMin(vector<int>& nums) {
if(nums.size()==0)
return 0;
if(nums.size()==1)
return nums[0];
for(int i=1;i<nums.size();i++){
if(nums[i-1]>nums[i])
return nums[i];
}
return nums[0];
}
};
Note:
Find the number which is smaller than the number before it.