LeetCode 3 Sum

Description

Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.

Note:
Elements in a triplet (a,b,c) must be in non-descending order. (ie, a ≤ b ≤ c)
The solution set must not contain duplicate triplets.

For example, given array S = {-1 0 1 2 -1 -4},

A solution set is:
(-1, 0, 1)
(-1, -1, 2)

The original problem is here.

The original code is here.

My Solution

I solve this problem in C++, as below:

/*
*3Sum
*Author: shuaijiang
*Email: zhaoshuaijiang8@gmail.com
*/
#include<iostream>
#include<vector>
#include<map>
#include<stdlib.h>
using namespace std;

class Solution {
public:
    vector<vector<int>> result;
    vector<vector<int>> threeSum(vector<int>& nums) {
        int size = nums.size();
        if(size <= 2)
            return result;
        sort(nums.begin(),nums.end());
        for(int i=0;i<size-2;i++)
        {
            if(i>0 && nums[i]==nums[i-1])
                continue;
            twoSum(nums, i+1,size-1, nums[i]);
        }
        return result;
    }
    void twoSum(vector<int> &nums, int start, int end, int target){
        vector<int> oneSet;
        
        while(start<end){
            if(nums[start]+nums[end]+target == 0){
                oneSet.push_back(target);
                oneSet.push_back(nums[start]);
                oneSet.push_back(nums[end]);
                result.push_back(oneSet);
                oneSet.clear();
                while(start<end && nums[start]==nums[start+1]) start++;
                while(start<end && nums[end]==nums[end-1]) end--;
                start ++;
                end --;
            }
            else if(nums[start]+nums[end]+target < 0)
                start ++;
            else
                end--;
        }
        return ;
    }
};

Note

For the problem, first sort the array. Then, for a number A in the array, select two numbers(B and C) from the set after A, which A+B+C=0. When select B and C, we find them from the head and tail of the array.


LeetCode 3 Sum
http://zhaoshuaijiang.com/2015/07/25/leetcode_3_sum/
作者
shuaijiang
发布于
2015年7月25日
许可协议